AP Chem Unit 13
Daily Answer Key
- B
- A
- C
- D
- A
- D
- A
- A
- A
- B
- B
- C
- B
- a) K =
[H2O]2
[H2]2[O2]
b) K = [Cl-]2[Fe3+]2
[Cl2][Fe2+]2
c) K = [Cu(NH3)42+]
[Cu2+][NH3]4
- a) K =
[H2]2[S2]
[H2S]2
b) K = [NH3]4[O2]7
[NO2]4[H2O]6
c) K = [NO2]2[H2]7
[NH3]2[H2O]4
d) K = [PCl3][Cl2]
[PCl5]
- Kp
= 1.6 x 1012atm-1
- 1.4
- a) K =
[NH3]2
[N2][H2]3
b) K = [ICl]2
[Cl2]
c) K = [BF3]2
[F2]3
- K = 10
where K = [products]
[reactants]
- K' =
55.6
- K = Kp(RT)-Δn
= Kp(RT) → K = 3.9 x 1013
- p(CO2)
= 0.201 atm; p(CO) = 0.549
- p(PCl5)
= 0.023 atm, p(PCl3) = 0.177 atm, p(Cl2) = 0.277 atm
- a) to
the left
b) to the right
c) no shift- the equilibrium is at
equilibrium
- Q =
0.065
- [NO] =
6.9 x 10-5 M; [N2] = [O2] = 3.4 x 10-3
- [NO] =
1.4 x 10-2 M; [N2] = 0.850 M; [O2] =
0.560 M
- [H+]
= 5.07 x 10-5 M
- [NH3]
= 0.198 M; [OH-] = [NH4+] = 1.9 x 10-3M
- 3.2 x
102
- [SbCl3]
= 7.3 x 10-3M; [Cl2] = 0.627 M; [SbCl5] =
0.173 M
- The
reaction would move left to right (fewer moles on the right side).
- a) The
reaction moves to the left.
b) The reaction moves to the right.
- Adding
NH3(g) drives the reaction to the left.
- Any
factor that will drive the system to the right.